Some of the methods previously discussed, such as delete
, work on files, links and directories. But how do you list all the directories at the top of a file system? How do you list the contents of a directory or create a directory?
This section covers the following functionality specific to directories:
You can list all the root directories for a file system by using the
FileSystem.getRootDirectories
method. This method returns an Iterable
, which enables you to use the
enhanced for statement to iterate over all the root directories.
The following code snippet prints the root directories for the default file system:
Iterable<Path> dirs = FileSystems.getDefault().getRootDirectories(); for (Path name: dirs) { System.err.println(name); }
You can create a new directory by using the
createDirectory(Path, FileAttribute<?>)
method. If you don't specify any FileAttributes
, the new directory will have default attributes. For example:
Path dir = ...; Files.createDirectory(path);
The following code snippet creates a new directory on a POSIX file system that has specific permissions:
Set<PosixFilePermission> perms = PosixFilePermissions.fromString("rwxr-x---"); FileAttribute<Set<PosixFilePermission>> attr = PosixFilePermissions.asFileAttribute(perms); Files.createDirectory(file, attr);
To create a directory several levels deep when one or more of the parent directories might not yet exist, you can use the convenience method,
createDirectories(Path, FileAttribute<?>)
. As with the createDirectory(Path, FileAttribute<?>)
method, you can specify an optional set of initial file attributes. The following code snippet uses default attributes:
Files.createDirectories(Paths.get("foo/bar/test"));
The directories are created, as needed, from the top down. In the foo/bar/test
example, if the foo
directory does not exist, it is created. Next, the bar
directory is created, if needed, and, finally, the test
directory is created.
It is possible for this method to fail after creating some, but not all, of the parent directories.
You can create a temporary directory using one of createTempDirectory
methods:
createTempDirectory(Path, String, FileAttribute<?>...)
createTempDirectory(String, FileAttribute<?>...)
The first method allows the code to specify a location for the temporary directory and the second method creates a new directory in the default temporary-fle directory.
You can list all the contents of a directory by using the
newDirectoryStream(Path)
method. This method returns an object that implements the
DirectoryStream
interface. The class that implements the DirectoryStream
interface also implements Iterable
, so you can iterate through the directory stream, reading all of the objects. This approach scales well to very large directories.
DirectoryStream
is a stream. If you are not using a try-
with-resources statement, don't forget to close the stream in the finally
block. The try-
with-resources statement takes care of this for you.
The following code snippet shows how to print the contents of a directory:
Path dir = ...; try (DirectoryStream<Path> stream = Files.newDirectoryStream(dir)) { for (Path file: stream) { System.out.println(file.getFileName()); } } catch (IOException | DirectoryIteratorException x) { // IOException can never be thrown // by the iteration. In this snippet, // it can only be thrown by // newDirectoryStream. System.err.println(x); }
The Path
objects returned by the iterator are the names of the entries resolved against the directory. So, if you are listing the contents of the /tmp
directory, the entries are returned with the form /tmp/a
, /tmp/b
, and so on.
This method returns the entire contents of a directory: files, links, subdirectories, and hidden files. If you want to be more selective about the contents that are retrieved, you can use one of the other newDirectoryStream
methods, as described later in this page.
Note that if there is an exception during directory iteration then DirectoryIteratorException
is thrown with the IOException
as the cause. Iterator methods cannot throw exception exceptions.
If you want to fetch only files and subdirectories where each name matches a particular pattern, you can do so by using the
newDirectoryStream(Path, String)
method, which provides a built-in glob filter. If you are not familiar with glob syntax, see
What Is a Glob?
For example, the following code snippet lists files relating to Java: .class, .java, and .jar files.:
Path dir = ...; try (DirectoryStream<Path> stream = Files.newDirectoryStream(dir, "*.{java,class,jar}")) { for (Path entry: stream) { System.out.println(entry.getFileName()); } } catch (IOException x) { // IOException can never be // thrown by the iteration. // In this snippet, it can // only be thrown by // newDirectoryStream. System.err.println(x); }
Perhaps you want to filter the contents of a directory based on some condition other than pattern matching. You can create your own filter by implementing the
DirectoryStream.Filter<T>
interface. This interface consists of one method, accept
, which determines whether a file fulfills the search requirement.
For example, the following code snippet implements a filter that retrieves only directories:
DirectoryStream.Filter<Path> filter = newDirectoryStream.Filter<Path>() { public boolean accept(Path file) throws IOException { try { return (Files.isDirectory(path)); } catch (IOException x) { // Failed to determine if // it's a directory. System.err.println(x); return false; } } };
Once the filter has been created, it can be invoked by using the
newDirectoryStream(Path, DirectoryStream.Filter<? super Path>)
method. The following code snippet uses the isDirectory
filter to print only the directory's subdirectories to standard output:
Path dir = ...; try (DirectoryStream<Path> stream = Files.newDirectoryStream(dir, filter)) { for (Path entry: stream) { System.out.println(entry.getFileName()); } } catch (IOException x) { System.err.println(x); }
This method is used to filter a single directory only. However, if you want to find all the subdirectories in a file tree, you would use the mechanism for Walking the File Tree.